We know that two similarly charged bodies repel each other. On the other hand, two oppositely charged bodies attract each other. The Coulomb’s law gives the expression for the force acting between two charged bodies (either similarly or oppositely charged).
Coulomb’s Law
Suppose, F is the force acting between two electrically charged bodies. Furthermore, as per Coulomb’s law, the expression of F will be,
Where ‘Q_{1}’ and ‘Q_{2}’ are the charges of the bodies. Whereas ‘d’ is the distance between the center of these charged bodies.
Permittivity of The Medium
The term ε_{0}ε_{r} in the expression of the Coulombic force (F) is the permittivity. In fact, it is the permittivity of the medium in which the charged bodies are placed.
Absolute Permittivity
In the term of the permittivity that is in ε_{0}ε_{r}, ε_{0} is the absolute permittivity of vacuum space. Hence, it will have a specific value. And the value of this ε_{0 }is 8.85×10^{-12} F/m.
Likewise, other mediums have different absolute permittivity values. For different scientific calculation, we need to recall those values as per requirement. Obviously it is difficult to remember all those values individually. But there is a solution from where the concept of relative permittivity comes.
Relative Permittivity
We consider the absolute permittivity of a vacuum space as a unity. Considering this as a unit we compare the actual permittivity of other mediums. In this way, it becomes easy to remember those numerical values. When we need to have the actual value of the permittivity of a certain medium, we just multiply the absolute permittivity of the vacuum space with that numerical value.
For example, the actual or absolute permittivity of mica is 44.27×10^{-12} F/m. So, if we divide this value with the absolute permittivity of vacuum we get 5 as a numerical value. It is needless to say that 5 is easier to remember than 44.27×10^{-12}. So whenever we need to have the absolute permittivity of mica we just multiply the absolute permittivity of vacuum with 5. We refer to this 5 as the relative permittivity of mica.
Formula of Relative Permittivity
Suppose, the absolute permittivity of a certain medium is ε. Then the relative permittivity of the same medium is ε/ε_{0}. This ε_{0} is the absolute permittivity of vacuum.
Significance of Permittivity
To understand the significance of permittivity we need to recall the expression of force acting between two charged bodies as per Coulomb’s law.
This expression shows that the force is directly proportional to the product of the charges.
Also, this expression shows that the force is inversely proportional to the square of the distance between the charged bodies.
Again 4π is a constant term. So, we can finally write,
Where ε is the permittivity of the medium. So, finally, we can say the force acting between two electrically charged bodies depends on the permittivity of the medium in which the bodies are placed.
Permittivity of Water
The relative permittivity of water is 80. Hence, the absolute permittivity of water is 80 times that of vacuum space.
Relative Permittivity of Air
The relative permittivity of the air is 1.0006. Besides this, we have considered relative permittivity of a vacuum space as 1. Since 1.0006 very nearly equals to 1. We can say the permittivity of air is the same as that of vacuum space.
Example
For example, let us consider a molecule sodium chloride. The sodium chloride molecule has an ionic bond between positive Na^{+} ion and negative Cl^{–} ion. Obviously we can consider the Na^{+} ion as a positively charged body. On the other hand, we can consider the Cl^{–} ion as a negatively charged body. Due to the coulombic force acting between these two opposite charges Na^{+} and Cl^{–} ions are attached together in the air. But when we dissolve sodium chloride salt in water, this coulombic force becomes 80 times weaker. Because the relative permittivity of water is 80. So, this weak attraction force no longer can attach the Na^{+} and Cl^{–} ions together. As a result, they de-touch from each other and stay in the water in the form of individual Na^{+} and Cl^{–} ions.
This is how the permittivity of a medium acts.
Unit of Permittivity
We can determine the unit of permittivity from the expression of the columbic force.
Unit of Relative Permittivity
The relative permittivity is nothing but the ratio of the absolute permittivity of medium to the absolute permittivity of vacuum.
Since ε_{r} is the ratio of two absolute permittivities having the unit of F/m; the relative permittivity is a unitless quantity.
Relative Permittivity of Different Mediums
SL. No. | Material | Permittivity (ε_{r})
(Approx) |
1 | Air | 1.0 |
2 | Paper | 1.4 |
3 | Teflon | 2.1 |
4 | Polypropylene | 2.4 |
5 | Polyethylene | 2.5 |
6 | Carbon-di-sulfide | 2.6 |
7 | Mylar | 3.1 |
8 | Polyimide | 3.4 |
9 | Silicon-di-oxide | 3.9 |
10 | Mica | 5.0 |
11 | Neoprene | 6.5 |
12 | Rubber | 7.0 |
13 | Diamond | 9.8 |
14 | Silicon | 11.6 |
15 | Ammonia | 26.4 |
16 | Methanol | 30.1 |
17 | Ethylene glycol | 37.4 |
18 | Glycerol | 42.5 |
19 | Water | 87.9 |
20 | Sulfuric acid | 96.8 |
- Capacitance – What is Capacitance?
- Capacitor What is a Capacitor? How does it work?
- Capacitors in Series and Capacitors in Parallel
- Multiplate Capacitor and Variable Multiplate Capacitor
- Energy Stored in a Capacitor
- Permittivity (Absolute Permittivity and Relative Permittivity)
- Charging of a Capacitor and Time Constant
- Discharging a Capacitor and Related Expressions
- Electric Field Intensity or Electric Field Strength
- Gauss’s Theorem or Gauss’s Law
- Electrical Potential and Potential Difference or Voltage
- Breakdown Voltage and Dielectric Strength
- Electric Flux and Faraday’s Tubes
- Equations of Poisson and Laplace
- Coulomb’s Law Statement and Explanation
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